2013-12-05 16:30:06Morris
[UVA][Easy] 12658 - Character Recognition
Write a program that recognizes characters. Don't worry, because you only need to recognize three
digits: 1, 2 and 3. Here they are:
.*. *** ***
.*. ..* ..*
.*. *** ***
.*. *.. ..*
.*. *** ***
SampleInput
3
.*..***.***.
.*....*...*.
.*..***.***.
.*..*.....*.
.*..***.***.
SampleOutput
123
只有123需要判別，單獨看第四行即可判別，星號剛好錯開。
#include <stdio.h>
#include <string.h>
int main() {
int n, i, j;
char s[1024];
while(scanf("%d", &n) == 1) {
scanf("%*s");
scanf("%*s");
scanf("%*s");
scanf("%s", s);
scanf("%*s");
for(i = 0, j = 0; j < n; i += 4, j++) {
if(s[i] == '*')
putchar('2');
else if(s[i+1] == '*')
putchar('1');
else
putchar('3');
}
puts("");
}
return 0;
}
digits: 1, 2 and 3. Here they are:
.*. *** ***
.*. ..* ..*
.*. *** ***
.*. *.. ..*
.*. *** ***
SampleInput
3
.*..***.***.
.*....*...*.
.*..***.***.
.*..*.....*.
.*..***.***.
SampleOutput
123
只有123需要判別，單獨看第四行即可判別，星號剛好錯開。
#include <stdio.h>
#include <string.h>
int main() {
int n, i, j;
char s[1024];
while(scanf("%d", &n) == 1) {
scanf("%*s");
scanf("%*s");
scanf("%*s");
scanf("%s", s);
scanf("%*s");
for(i = 0, j = 0; j < n; i += 4, j++) {
if(s[i] == '*')
putchar('2');
else if(s[i+1] == '*')
putchar('1');
else
putchar('3');
}
puts("");
}
return 0;
}