2012-03-26 22:33:54Morris
[UVA][JAVA] 10023 - Square root
Square root
Square root |
The Problem
You are to determinate X by given Y, from expression
The Input
The first line is the number of test cases, followed by a blank line.
Each test case of the input contains a positive integer Y (1<=Y<=101000),
with no blanks or leading zeroes in it.
It is guaranteed, that for given Y, X will be always an integer.
Each test case will be separated by a single line.
The Output
For each test case, your program should print X in the same format as Y was given in input.
Print a blank line between the outputs for two consecutive test cases.
Sample Input
1 7206604678144
Sample Output
2684512
就算是 JAVA 也沒有大數開根號, 只好採用二分逼近,
不過會有測資不是完全平方數,
for example
x = 1000 you should output y = 31
這個部份讓我錯了很多 ...
import java.util.Scanner;
import java.math.BigInteger;
public class Main {
public static void main(String[] args) {
Scanner keyboard = new Scanner(System.in);
String x;
BigInteger l, r, m, n;
int t = keyboard.nextInt();
while(t != 0) {
t--;
x = keyboard.next();
n = new BigInteger(x);
l = BigInteger.valueOf(1);
r = BigInteger.valueOf(10).pow(x.length()/2+1);
m = BigInteger.valueOf(0);
while(l.compareTo(r) <= 0) {
m = l.add(r).shiftRight(1);
if(m.multiply(m).compareTo(n) == 1) {
r = m.subtract(BigInteger.valueOf(1));
} else if(m.multiply(m).compareTo(n) == -1) {
l = m.add(BigInteger.valueOf(1));
} else
break;
}
if(m.multiply(m).compareTo(n) > 0)
m = l.subtract(BigInteger.valueOf(1));
System.out.println(m.toString());
if(t != 0)
System.out.println("");
}
}
}